0=-p^2+50p

Solution for 0=-p^2+50p equation:

0=-p^2+50p

We move all terms to the left:

0-(-p^2+50p)=0

We add all the numbers together, and all the variables

-(-p^2+50p)=0

We get rid of parentheses

p^2-50p=0

a = 1; b = -50; c = 0;
Δ = b2-4ac
Δ = -502-4·1·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50}{2*1}=\frac{0}{2}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50}{2*1}=\frac{100}{2}
=50
$